Weighted Average
Essential for mixture problems where groups have different sizes.
๐ Example: Class Average
Class A (10 students) has average 80. Class B (20 students) has average 95. Overall average?
\(\text{Avg} = \frac{10(80) + 20(95)}{30} = \frac{800 + 1900}{30} = 90\)
Result: 90.